Structural Steel Takeoff Example James Sneath, Associate Director of Cost Management for Turner and Townsend, and Ian Taylor, Project Manager for Turner and Townsend, discuss Quantity Take Off and Measurement. Estimating cut and fill costs is taught along with a detailed example of using cut and fill software. Also covered in this module is the topic of deep foundations, concrete foundations and structural steel, measurement, masonry, glass curtain wall, facade and wall finishes.

This course introduces the types of cost estimation from the conceptual design phase through the more detailed design phase of a construction project. In addition, the course highlights the importance of controlling costs and how to monitor project cash flow. Students will work on a break-even analysis of construction tasks in a project.

Просмотреть программу курса Получаемые навыки Cash Flow, Cost, Cost Control, Cost Estimate

Преподаватели Ibrahim Odeh, Ph.D., MBA Instructor, Department of Civil Engineering and Engineering Mechanics, Columbia University

Okay, on to example number two.

You are a contractor that has been given a set of construction documents, and

have been asked to quantify the following conditions.

There are ten rows of steel 16K2 joists

that will be a total of 135 linear feet each.

Additionally, there are 10 rows of W27 by 114 structural

members that will be a total of 155 linear feet each.

Finally, 18 gauge metal decking will be used to support the future concrete floor.

So, how do we go about this?

First, we want to calculate the total weight of the steel beams.

We know from our example that we have 10 members that are 155 linear feet each.

Thus, the calculation becomes 10 times 155 for

a total of 1,550 linear feet.

Multiplying the linear feet by the total weight,

brings us to a grand total of 176,700 pounds.

Next, you must calculate the weight of the joists.

Understanding that we have a 16K2 member.

There are ten of each and each are 135 linear feet in length.

Thus, we come to a total of 1,350 linear feet.

We must now refer to the table previously used to determine

the weight per linear foot type for the 16K2 Joist.

Going back to our previous example,

we can see that Joist designation 16K2 has a depth of 16 inches and

has an approximate weight of 5.5 pounds per linear foot.

Thus, we solve for the total weight based on joist linear footage.

1,350 times 5.5 pounds per linear

foot comes to a total of 7,425 pounds.

Next, you must solve for all of the structural steel connections.

The first member which has a total weight of 176,700

pounds we multiplied by 1.10 to capture a total weight of 194,370 pounds.

Secondly, the steel joists 7,425

pounds we multiplied by 10% for

a grand total of 8,167.5 pounds.

Next, we must convert the steel into tonnage.

Starting with the W27 X 114 member,

we divide 194,370 pounds by 2000 to come up with a total of 97.19 tons.

Similarly with the 16K2 joists, you have a total weight of 8,167.5 pounds.

Divide that by 2,000 and you come up with a total of 4.08 tons.

Finally, quantify the area of the floor plan and

in order to capture the steel decking.

We know the structural members are 135 feet inlength by 155 feet in length.

Thus, the total square footage for the floor plan is 20,925 square feet.

Finally, this table will indicate how each of the individual

portions of our problem will need to be quantified.

We hope you enjoy this module.

Thank you and we'll see you next time.

Okay, so on to example number two.

You're a contractor that has been given a set of construction documents and

have been asked to quantify the following conditions.

You have a total of ten rows of

16K2 joists that are at a total

length of 135 linear feet each.

Secondly, you have ten rows of W27 by 114

structural steel members at a total of 155 linear feet each.

Finally, 18 gauge steel decking will

be used to cover the entire floor area for

a future concrete floor.

So, to begin.

First, you're going to want to quantify the weight of these steel

beams starting with a W27 by 114.

We understand that there are a total of ten members at 155 linear feet each.

Thus, you have a grand total of 1,550 linear feet.

You have a total of 10 members at 135 linear feet each.

Thus, the calculation becomes 10 x 135 linear feet for

grand total of 1350 linear feet.

So, the next operation we want to perform is calculating the weight

of W27 x 114 social members.

As in the previous example,

you would multiply the total linear footage, 1,550, by 114.

Thus, the calculation becomes

1550 times 114 for

a total of 176,700 pounds.

Secondly for the joist, we would need to refer back to

the manufacturers table which we provided for earlier presentation.

We learned that a 16K2 joist has a depth of 16 inches and

has a nominal weight of approximately,

5.5 pounds per linear foot.

Thus, the operation becomes 1,350 times 5.5 per linear foot.

Which brings you to a grand total of 7,425 pounds.

Next operation you're going to want to perform is solving for

all of the steel connections.

As we learned earlier in our presentation,

we add typically a 10-13% markup depending on the location of the project.

And for our example purposes,

we will be multiplying 176,700 pounds by a factor of 10%.

That calculation is performed by multiplying

176,700 pounds by one, which is the principle,

times temperature markup for a grand total of.

194, 370, 000, Again for the joisting,

you are going to make an assumptions of a 10% extra in weight for the connections.

Thus, that calculation becomes

7,425 times the principle and

a 10% markup for

a total of 8,167.5 pounds.

Next, we want to convert for tonage.

That is simply performed by dividing by 2000.

In then a case of our W27 by one fourteen member,

that calculation comes out to 97.19 tons.

And for the joists, that comes to a total.

Finally for the decking, you'll remember that we need to quantify

the square footage of the total floor area.

With more complex problems like this, I find it helpful to draw out to help you

envision what it is you've been asked to do.

So you have an area, Of 155 linear feet.

Multiply it by 135 linear feet.

Thus, that calculation becomes 155 x 135 for

a total area of 20,925 square

feet to develop all this area.

Thus, you've captured the three main criteria that has

been asked in the problem.

We hope you've enjoyed this presentation.

Thank you very much and we'll see you next time.

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